Hari

• Jun 4th, 2006

 

when the two trains cross themselves,in 18 seconds they will be move 24meters and 21 metres by their speed.so the trains length is 22.5 meters.

vkparthipan

• Jun 19th, 2006

 

don tconfuce this is correct one..

first train length x metre

same length so 2nd train x metre

total length 2x

first train speed in km/hr=42

conversion to me/sec  42*8/15=35/3 m/s

2nd=40/3 m/s

relative speed opposite so 75/3

totaldistance/speed=time

2x/75/3=18

6x/75=18

so x=225

Divya Harnadh Babu Sanam

• Jul 9th, 2006

 

42 kmhr=42*5/18

48 kmhr=48*5/18

therefore=(42+48)*5/18=25 msec

so 18=(x+x)25

x=22.5 metres

vishwa828

 Profile Answers by vishwa828 

• Dec 7th, 2006

 

use the formula t=((a+b)/(u+v)) where a,b are the train lengths and u, v are the velociities of the trains and t is the time so we get 225 m as answer here!