A goes to school at 4 kmph and reaches 10 minutes before schedule and at 3 kmph reaches 10 mins after schedule. Find the distance

4 km

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vamshi

  • Sep 18th, 2011
 

10/9(t-10)=5/6(t+10) t=70 min.

Substitute the value in one of the equations you will get the answer in fraction

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