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One man Buy two cows for Rs.200.He sold the cows for Rs.210.One he sold for 10% profit and another he sold for 10% loss.Then what is the cost price of each cow?
90 rs,--gives 10 perc loss110 rs, --gives 10% profittotal=210
diju
- Oct 18th, 2006
one he bought for 50other for 150first he sold for 45second for 165
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Hello friends I need answer with working steps for the following questions as soon as possible as I have only one day to prepare for Infosys test.1)There was a person who smoked a lot .One day he decided to quit his habbit,but he had 27 cigarettes with him. So he started smoking them one by one ,to finish them. He had the habit of smoking only 2/3rd of it and leaving the rest butt. latter he found out that by joining 3 butts he can form 1 cigarette. So, tell haw many cigarettes in all he smoked.2)There are 100 men in town. Out of which 85% were married, 70% have a phone, 75% own a car, 80% own a house. What is the maximum number of people who are married, own a phone, own a car and own a house ? 3)One day Harry and I set our watches together. None of us was aware that my watch was getting faster by 2 min per hour and Harry’s watch was getting slower by 1 min per hour. After sometime, we discovered that my watch was 1 hr ahead of Harry’s watch. Can you find out after how long we noticed this ?
yusufqtv
- Jun 3rd, 2006
According to me the solution is:Every above friends are forgetting smoker has the habit of smoking 2/3rd of what he has at one time.so aproach is this way(2/3)*27+(18/3)+(2/3)*9+(6/3)+(2/3)*3+(2/3)=104/3 cigs.
bijoy's
- Apr 10th, 2006
Hai, firstly 27 cigretes leaving 27butts hence 27/3=9 more cigerettes.so now a total of 36 cigerettes already. now again 9/3 leaving 3 more which again3/3 leaves one more .hence a total=27+9+3+1=40 cigerettes.
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In a maThematic there are 1,2,3,....9 cities and each number corresponds to a city. Now an airflight route is to be established between two cities such that the numeral formed is divisible by 3. (eg. if 1 and 2 are connected then it satisfies the condition). Find out the number of cities which are connected to city 8, either directly or indirectly.
5 cities
vijay_1437143
- Dec 23rd, 2010
Possible combinations4Â Â Â 0Â Â no of ways to arrange =13Â Â Â 1Â Â no of ways to arrange =2*92Â Â Â 2Â Â no of ways to arrange =2*92Â Â Â Â 1Â Â 1Â Â no of ways to arrange =3*9*81Â Â Â Â 1...
shivanand_jha
- Oct 9th, 2010
Here we just have to check the no. divisible by 2. i.e. if ab is divisible then ba is also divisible.Now, checking for 8-1828384858687898.only 18,48,78 are divisible by 3.hence answer is 3 cities
