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If the program (myprog) is run from the command line as myprog 1 2 3 , What would be the output? main(int argc, char *argv[]) { int i; for(i=0;i<argc;i++) printf("%s",argv[i]); }
A) 1 2 3B) C:MYPROG.EXE123C) MYPD) None of the above
sunilkanna
- Oct 21st, 2009
The answer is b. because command line argument includes file path as first argument.
prabhjots
- Feb 6th, 2008
The result will bec:mypgm.exe123becoz argv[0] will be the location of ur program(be it c: or d:)
