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What would be the output of the following program? main() { int y=128; const int x=y; printf("%d",x); }
A) 128B) Garbage valueC) ErrorD) 0
Amit
- Dec 12th, 2005
Correct ans is A) 128
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printf("%d, %d ", j++ , ++i);
}
">main(){ int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i);}
A) 20, 9, 19, 10B) 20, 9, 20, 10C) 20, 10, 20, 10D) 19, 9, 20, 10
abhimanipal
- Jan 28th, 2010
The O/P in this question is not compiler dependant. The language specification of C clearly states that the arguments to the function are supposed to be passed from right to left. So irrespective of the compiler there should be only 1 answer20, 9, 19, 10
sittoop
- Feb 26th, 2009
This is supposed to be same in both C and C++. According to ISO ANSII standard the answer to this is "undefined".
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}
">main(){ int i = 100; clrscr(); printf("%d", sizeof(sizeof(i)));}
A) none of the aboveB) 4C) 100D) 2
gau_bhatnagar
- Dec 29th, 2005
Internal sizeof(i) gives output 2.2 is integer so outer sizeof()again gives output 2.
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}
">main(){ printf("%d, %d", sizeof('c'), sizeof(100));}
A) 4, 100B) 2, 100C) 2, 2D) 4, 4
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}
">const int perplexed = 2;#define perplexed 3main(){ #ifdef perplexed #undef perplexed #define perplexed 4 #endif printf("%d",perplexed);}
A) none of the aboveB) 4C) 2D) 0
indira.moparthi
- Apr 19th, 2009
Perplexed is a const variable. In the # define we are trying to modify the value which leads to an error.
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How will you print % character?
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}">
union u{ struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i;}u;main(){ u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l);}
A) 40, 4, 0B) 100, 4, 0C) 0, 0, 0D) 4, 4, 0
opal_sybil
- Aug 28th, 2010
The struct notation int i : 4; specifies the size of integer i in bits, so the value of i will be represented by 4 bits. In this case we have a signed int with a possible values of -8 to 7. Whe...
yba
- Jul 10th, 2007
The output should contain 100 as the first number.The union declares that st.i is a 4-bit field, and 100 can fit in 4 bits, however, you need to know how your compiler allocates bitfields. Are t...
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}
">main(){ int i; float *pf; pf = (float *)&i; *pf = 100.00; printf("n %d", i);}
A) Some Integer not 100B) 100C) Runtime error.D) None of the aboveExplanation: Output = 0
wrongmove
- Dec 11th, 2008
IEEE-754 Floating is used to store Float. So while storing float s store with encoded format. When i is used to access this value it reads 4 bytes which are nothing but IEEE-754 Floating encode. if you type that number in IEEE-754 Floating calculator it will show it as 100.
bipi2g
- Jun 28th, 2007
Yes, Compile and run by Dev-C++. Output is garbage (i see 1120403456 in output window).
