JAVASCRIPT difficulty

Hi
I am currently learning javascript and I came across this exercise question:

Code
<html>


        <head>


        </head>


        <body>


                <script language="javascript">


                        var numbers = [-19, -7, -55, 78, 54, 60, -53, 35, 56, 42, 20, 77, 93, -41, -24, -60, 7, 86, 14, -99];


                        alert (secondLargest(numbers));


                        alert (reverse("CSY2028"));


 


                        function secondLargest(num){


                                return 0;


                        }


 


                        function reverse(str){


                                return "";


                        }


                </script>


        </body>


</html>


 
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The scenario is that I have to
Define a function secondLargest() that takes an array and returned the 2nd largest number.
AND
Define a function reverse() that computes the reversal of a string. For example, reverse("Hello world") should return the string "I love Javascript".
I have had done many attempts to solve the task but I run into problems.
Any help? it would be appreciated

GlennYemoh
Profile Answers by GlennYemoh Questions by GlennYemoh
Oct 2nd, 2014
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Questions by GlennYemoh

JavaScript

Answer

Showing Answers 1 - 6 of 6 Answers

Oleg

Dec 5th, 2014

Here is it.

Code
var numbers = [-19, -7, -55, 78, 54, 60, -53, 35, 56, 42, 20, 77, 93, -41, -24, -60, 7, 86, 14, -99];


function secondLargest(num){


  var mn = num[0];


  for(var i=1; i<num.length; i++)


    if(mn < num[i])mn = num[i];


  return mn;


}


function reverse(str){


  var rstr = "";


  for(var i=0; i<str.length; i++){


    rstr = rstr + str.charAt(str.length - i -1);


  }


  return rstr;


}


alert (secondLargest(numbers));


alert (reverse("CSY2028"));

Anshul

Jul 1st, 2019

Code
var numbers = [-19, -7, -55, 78, 54, 60, -53, 35, 56, 42, 20, 77, 93, -41, -24, -60, 7, 86, 92, 14, -99];


 


 


function secondLargest(num){


 


 


  var first = num[0];


  var second = num[0];


 


 


  for(var i=1; i<num.length; i++)


 


 


    if(first < num[i]){


                second = first;


        first = num[i];


        }else{


                if(second < num[i]){


                        second = num[i];


        }


    }


 


  return second;


}


 


function reverse(str){


 


 


  var rstr = "";


 


 


  for(var i=0; i<str.length; i++){


 


 


    rstr = rstr + str.charAt(str.length - i -1);


 


 


  }


 


 


  return rstr;


 


}


 


alert (secondLargest(numbers));


alert (reverse("CSY2028"));