std.approach

 Profile Answers by std.approach 

• Jun 4th, 2013

 

Its simple.
1. do calculate the sum of numbers from 1 till 100. is about (1+100)*(100/2)=5050
2. iterate and summarize all elements of container (array).
3. each number is unique in the container, so the difference between 5050 and the sum (from point 2) gives us an answer.

harshitha

• Feb 7th, 2014

 

Calculate the sum of 1 to 100 i.e sum=(1+100)*(100/2)=5050

Code
int main()


{


      int sum=5050,res=0,temp=0,i;


      int str[200]={1,2,3.............99,100};


      for(i=0;i<100;i++)


      {


           res=res+str[i];


       }


       temp=sum-res;


       printf("missing number is %d


",temp);


       getch();


}