Santosh Nemani

• Mar 20th, 2012

 

#!/bin/ksh +x


df -kl|grep "<8[0-9]%>" > dfout.log
df -kl|grep "<9[0-9]%>" >> dfout.log
df -kl|grep "100%" >> dfout.log

Tabrejkhan

• Sep 3rd, 2012

 

$ df -k|grep "1[0-9]%"
O/p:
2031440 342300 1584284 18% /
3047184 392216 2497684 14% /opt
190403 31064 149509 18% /osmf/mgmt/scheduler
3047184 391464 2498436 14% /var
/dev/cciss/c0d0p1 101086 15970 79897 17% /boot

Tubal Deen

 Profile Answers by Tubal Deen 

• Jun 23rd, 2014

 

Code
df -h | awk {print $5} | sed s/.$// | egrep 8[0-9]|9[0-9]

Vinil Mehts

• Aug 26th, 2014

 

You can use awk to check the % free space. Example stated as follows in UNIX.

Code
df -k|


awk 


{


if $5>80;


print $5


 }

Rohit

• Feb 18th, 2015

 

df -h | awk {print $5 " " $6} | grep -vi use |grep ^[8|9][0-9]|100

abhinav

• Jan 19th, 2016

 

grep -r string dirname.

If you want to search in current directory then
grep -r string .

Raans

• Sep 6th, 2016

 

for a in df -h|awk {print($5" "$6)}`
do
b=`echo $a|awk -F"%" {print ($1)}`

if [$b -gt 80]
then
echo $a
fi
done

Anupam Kumar

• Nov 2nd, 2016

 

Here it is-

Code
ls -l | grep ^d

suman chakraborty

• Nov 8th, 2016

 

df -k | tr -s " "|awk {FS=" ";}{if ( substr($5,1,2) >= 80 ) print $1;}

Asish

• Dec 28th, 2017

 

df -h | tr % /32 | awk $5 > 80