Sainath Rao

• Dec 6th, 2011

 

Code
int calfactorial (int x)


{


 int finalx = 1;


 if (x==1) return 1;


 for (int i = 1; i <= x; ++i) finalx = finalx * i;


 return finalx;


}

Paul_Singh

 Profile Answers by Paul_Singh 

• Feb 7th, 2012

 

Should use the fact that in n!, n is only a positive integer. As the number increase fairly rapidly, maybe a double return is better than a signed int.

Code
double factorial( unsigned int n )


{


    double result = 1;


    for(unsigned int i = 1; i <=n; i++ )


    {


        result*=i;


    }


    return result;


}

FHGCVJ

• Apr 14th, 2012

 

..

Code
int calfactorial (int x)


{


 int finalx = 1;


 if (x==1||x==0) return 1;


 for (int i = 1; i <= x; ++i) finalx = finalx * i;


 return finalx;


}

Anugya Singh

• Sep 4th, 2012

 

Code
#include<iostream.h>


#include<conio.h>


void main()


{


clrscr();


int a,i,f=1;


cout<<"Enter the Number whose factorial value is to be find 


";


cin>>a;


for(i=a;i>0;i--)


{


f=f*i;


}


cout<<"Fctorial is "<<f;


getch();


}

sakshi

• Oct 4th, 2012

 

Code
class factorial


{


public static void main(String args[])


int f=1,i,n;


n=Convert.ToInt32(Console.ReadLine());


for(i=1;i<=n;i++)


{


f=f*i;


}


Console.WriteLine("factorial of the no :"+f);


 


Console.ReadKey();


}