Bhoomika sharma Profile Answers by Bhoomika sharma Questions by Bhoomika sharma Dec 29th, 2008 See, we a re given wid sum xtra information:Here, we know a su apervisor is also an employee,thus, given:60% of supervisors are male : so, 60% of 30% of supervisors are male=> 18% are male=> 12% are femaleso, P(either a male or a female employee)== 18/100+12/100=0.3 as total number of employees are 100.Thus,0.3 is answer.

rajintouch Profile Answers by rajintouch Jan 23rd, 2009 It was clearly mentioned that there are 40% of male employees inthe office....then we can conclude that the answer is "male:female=4:6"

unrealvicky Profile Answers by unrealvicky Aug 16th, 2010 I would say probability of randomly chosen a male employee is 22% while that of female is 48%. Base on my understanding of the question, let 'x' be the total employee (supervisors and ordinary employees) supervisor: 30% of 'x' = 0.3x male supervisors: 60% of 0.3x = 0.18x and female supervisor: 40% of 0.3x = 0.12x total male employees: 40% of 'x' = 0.4x therefore, number of ordinary male employee = 0.4x - 0.18x = 0.22x => P(male employee) = 0.22x/x = 0.22 i.e. probability of male employee is 22% total female employees: 60% of 'x' = 0.6x therefore, number of ordinary female employee = 0.6x - 0.12x = 0.48x => P(female employee) = 0.48x/x = 0.48 i.e. probability of female employee is 48% I hope I've interpreted the question correctly.

## In a office, 30% are supervisors, 40% are male employees, 60% of supervisors are male. Probability that a random chosen employee is a male or a female?

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