dinesh_sun7

 Profile Answers by dinesh_sun7 

• May 21st, 2008

 

the answer in 3188 since 8,5 is the 54th location in the array and each bytes occupying 4 bytes it will be in the starting addres 3000+188=3188 ok?

SpandanaMohan

 Profile Answers by SpandanaMohan 

• May 21st, 2008

 

Since the address starts at 3000 and allocating 4 bytes to each location, i guess the address of X(8,5) will be 3212...correct??

anon1987

 Profile Answers by anon1987 

• Dec 7th, 2009

 

In a two-dimensional array, X (9, 7), with each element occupying 4 bytes of memory, with the address of the first element X (1, 1) is 3000, find the address of X (8, 5).


Ans:     3000 + 4(8 * 7) + 4 * 5
            = 3000 + 224+ 20
            = 3244