There are 45 members in a group. 9 members have shoes but no hats. 18 members have shoes. How many members are there who have only hats? a)12 b) 19 c) 27 d) 18
D)18.
no. of members who have both hats and shoes= 18 - 9 = 9
no. of members who have hats = 45 - 18 = 27
no. of members who have hats only hats = 27 - 9 = 18.
no of students have both shoes and hats is: 9 since 18 have shoe not mention about hat so (18-9) no of students have shoe alone is:9 from the total students 45, 45-(9+9)=27
Showing Answers 1 - 20 of 20 Answers
Neelam RAwat
Dec 1st, 2006
18 member have shoes(no mention of hats)
9 member have shoes but not hat
i.e the member who are havin only hats are 45-18=27
snehal
Dec 1st, 2006
d) 18
chandrakanth
Dec 17th, 2006
no. of members who have both hats and shoes= 18 - 9 = 9
no. of members who have hats = 45 - 18 = 27
no. of members who have hats only hats = 27 - 9 = 18.
dear.chandru12
Feb 20th, 2007
no of students have both shoes and hats is: 9 since 18 have shoe not mention about hat so (18-9) no of students have shoe alone is:9 from the total students 45, 45-(9+9)=27
varun sabharwal
Mar 3rd, 2007
since their are 9 members with shoes only and 9 others with hats and shoes so if we have to select one of the options we have to go with 27
Sandipan Dey
Mar 21st, 2007
As the question says find those who have only hats the answer is 27.... total students with shoes=18(among these 9 dont have hats) so no. of students with only hats=45-18=27
Eric9
Oct 26th, 2007
27
B-cause.
There is three groups.
1. Shoes and NO Hat
2. Shoes and Hat
3. No Shoes and Hat
<<If there is some members who doesn't hav anything,
the question hav to mention about that. BUT! There is no mention about that.
so, I can suppose that there is no member who doesn't hav anything. >>
use the venn diagrams formulae : A union B = A + B - A intersection B where AUB=45 (total) no.of people who've shoes A=18 no.of people who've hats B=? no.of people who've only shoes but not hats A-B = 9 no.of people who've shoes and hats A n B = 9 no.of people who've only hats but not shoes B-A = ? apply formula 45=18+B-9 => B=36 => B-A= 36-9 =27 Ans:c
There are 45 members in a group. 9 members have shoes but no hats. 18 members have shoes. How many members are there who have only hats? a)12 b) 19 c) 27 d) 18
no. of members who have both hats and shoes=
18 - 9 = 9
no. of members who have hats = 45 - 18 = 27
no. of members who have hats only hats = 27 - 9 = 18.
Questions by khalid_it
Editorial / Best Answer
Answered by: dear.chandru12
no of students have both shoes and hats is: 9 since 18 have shoe not mention about hat so (18-9)
no of students have shoe alone is:9
from the total students 45, 45-(9+9)=27
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