Raj

• Jul 19th, 2005

 

The product of AB and D is ABD (i.e., EEE/C)

MOWGLI

• Aug 3rd, 2005

 

by hit n trial eee=444 => 444=37 * 12 (factors) 
 
ab=37 cd=12 
which satisfies the condition 
e*cd-ab=cc => 4*12-37=11=cc

sonam

• Aug 26th, 2005

 

answer of this question is BE 
i dont know how it is. 
but this is correct answer.... 

gauravghai

• Jun 25th, 2006

 

BE

kandukurisunil2005

 Profile Answers by kandukurisunil2005 

• Jun 8th, 2009

 

The Product of AB and D is......BE.

if A=3, B=7, C=1, D=2 & E=4

1st Condition--product of AB and CD is EEE...37 * 12 = 444

2nd Condition--if AB is subtracted from the product E and CD then CC....

4 * 12  -  37  = 48 - 37 =11

now the

3rd Condition..The product of AB and D ...is BE

37 * 2  =74.

which is Nothing But BE.

shilpasbhatt

 Profile Answers by shilpasbhatt 

• Dec 29th, 2009

 

Given,
(1) AB*CD=EEE
(2)E*CD-AB=CC

We can write eqn (1) as AB*CD=111*E----- (3), Where E is either 1 or 2 or 3 or...
 Factors of 111 is 37 and 3

So (3) becomes AB*CD=37*3E

Now, either AB=37 or CD=37

Case 1: suppose CD=37,
then, (2) becomes, E*37-AB=33
From (3), AB*37=37*3E ==> AB=3E
.'. 37E-3E=33
suppose E=1, (37-3)!=33, So E!=1
suppose E=2, (74-6)!=33, So E!=2
similarly, E!=3 or 4 or 5 or...
==> CD!=37

Case 2: Suppose AB=37,
then from (1) CD=3E
then (2) becomes E*3E-37=CC
                             3E^2-37=11 or 22 or 33 or.....
                             3E^2=48 or 59 or 70 or.....
            When c=1, E^2=16, the perfect square.
                         ==> E=4

Therefore AB=37, E=4

From (1) 37*CD=444
==> CD=12

So, A=3, B=7, C=1, D=2 and E=4

Product of AB and D is 37*2=74, ie., BE
           

sandeep.thadka

 Profile Answers by sandeep.thadka 

• Jan 18th, 2011

 

BE is the correct answer

check it
ans:
A=3
B=7
C=1
D=2
E=4