Output of these programs.

Code
 


struct Foo


{


char *pName;


};


main()


{


struct Foo *obj = malloc(sizeof(struct Foo));


clrscr();


strcpy(obj->pName,"Your Name");


printf("%s", obj->pName);


}


 
Copyright GeekInterview.com

a. Your Name

b. compile error

c. Name

d. Runtime error

Code
 


struct Foo


{


char *pName;


char *pAddress;


};


main()


{


struct Foo *obj = malloc(sizeof(struct Foo));


clrscr();


obj->pName = malloc(100);


obj->pAddress = malloc(100);


strcpy(obj->pName,"Your Name");


strcpy(obj->pAddress, "Your Address");


free(obj);


printf("%s", obj->pName);


printf("%s", obj->pAddress);


}


 
Copyright GeekInterview.com

a. Your Name, Your Address

b. Your Address, Your Address

c. Your Name Your Name

d. None of the above

hardeep85
Profile Answers by hardeep85 Questions by hardeep85
Aug 15th, 2006
3
2081

Questions by hardeep85

Answer

Showing Answers 1 - 3 of 3 Answers

vipin gupta
Profile Answers by vipin gupta Questions by vipin gupta

Oct 16th, 2006

The answer to both programs is 'd'
vipin

wizard

Feb 27th, 2007

In first case the mem is allocated for struct but not for pName. so you will get runtime error as "Segmentation fault".

In second case also you will get the same, because here allocating memory and then freeing the object and then using in the printf statement. So obj is freed and your refering an unallocated memory. so you will get the same error.