indupriya

• Apr 9th, 2006

 

program for above question import java.util.*; 2: 3: class Name { 4: public static void main(String[] arguments) { 5: String names[] = { "Peter", "Patricia", "Hunter", "Sarah", 6: "Gabe", "Gina", "Rob", "John", "Zoey", "Tammy", "Robert", 7: "Sean", "Paschal", "Kathy", "Neleh", "Vecepia" }; 8: System.out.println("The original order:"); 9: for (int i = 0; i < names.length; i++)10: System.out.println(i + ": " + names[i]);11: Arrays.sort(names);12: System.out.println("The new order:");13: for (int i = 0; i < names.length; i++)14: System.out.println(i + ": " + names[i]);15: }16: }

Alex

• Mar 2nd, 2007

 

String names[] = {"Peter", "Patricia", "Hunter", "Sarah","Gabe", "Gina", "Rob", "John", "Zoey", "Tammy", "Robert","Sean", "Paschal", "Kathy", "Neleh", "Vecepia", "Robert"};
TreeSet set = new TreeSet(Arrays.asList(names));
for (String name : set)
System.out.println(name);

shriddhas

 Profile Answers by shriddhas 

• Aug 26th, 2009

 

import java.util.Arrays;

class TestArray{
 public static void main(String args[]){
  int arr[] = new int[]{2,5,1,1,2,3,4,3,4,4,5,5,15,35,5,5,45,5,5,5,65,5,5,5,5,5,5,6,17,7,7};
  Arrays.sort(arr);

  int newArray[] = new int[arr.length];
  

  int temp =0;
  int count =0;

  for(int i=0; i<arr.length; i++){
   temp = arr[i];
   int val = i+1;
   if(val < arr.length){
     if(temp==arr[val])
      continue;
   }
    newArray[count++] = temp;
  }

  for(int i=0; i<newArray.length; i++){
   System.out.println(newArray[i]);
  }
 }
}

ajithg4u

 Profile Answers by ajithg4u 

• Aug 26th, 2009

 

Sort the array and compare the adjacent elements if the adjacent elements are equal then there will be duplicates.