What would be the output of the following program? main() { const int x=5; int ptrx; ptrx=&x; ptrx=10; printf("%d",x); } a) 5 b) 10 c) Error d) Garbage value

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shrutimitra
Profile Answers by shrutimitra

Oct 23rd, 2005

5. Because the value of x can not be modified .

Rage
Profile Answers by Rage

Dec 5th, 2005

The Answer is C. ERROR!First of all you cant store the address(&x) of a const int in a normal integer pointer(*ptrx)we need to declare the pointer(ptrx) as "const int *ptrx ; ". Well even after this you cant change the value of *ptrx since its a const pointer. Therefore it results in a ERRORThe error before modification wud be "cannot conver ' const int * ' to ' int * ' "