If A, B, C are having x, y, z marbles initially, A has given the same number of marbles to both B and C as they have. Next B has given the same number of marbles to both Aand C as much they already have, Similarly C also given to A & B. then how many marbles that B has finally?

2(3y-x-z)

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sunny

  • Mar 22nd, 2007
 

b has 2(z-x+y) marbles left with him

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