There are 10 items in a box, out of which 3 are defective. 2 balls are taken one after the other.What is the probability that both of them are defective?

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hans

  • Aug 4th, 2005
 

(3/10*2/9)=1/15

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ather_jmi

  • Jul 5th, 2007
 

Probability of an event is the number of cases resulting in that event divided by total number of cases:
now 2 balls can be chosen from 3 defectice ones in 3C2 ways
and there are 10 C2 ways of choosing 2 balls from a total of 10 balls hence:

3C2   /  10C2  =(3*2)/(10*9)

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