Write a program that continues to ask the user to enter any decimal number and calculate it’s binary,octal and hexadecimal equivalent.

Badugu

• Mar 11th, 2015

Please try following:

Code
#include<iostream>
#include<fstream>
#include <bitset>
 
using namespace std;
 
int main()
{
    int i,j;
    cout<<"Enter a decimal Number:";
    while (cin>>i) {
                 
          cout<<"Hexa Decimal:"<<std::hex<<i<<"     Octal:"<<std::oct<<i<<endl;
          std::bitset<8> x(i);
          cout<<"Binary:"<<x<<endl;
          cout<<"Enter a decimal Number:";
          }
          
          return 0;
          }
 

rohit suri

• Sep 11th, 2014

Code
 
int binary_function(int num)
{
   if(num==1)
      return 1;
  else 
    return binary_function(num/2)*10+(num%2);
}
 

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Write a program that takes an integer and displays the words number of that value. For example, 10->ten 121->one hundred twenty one

Subrata Laha

• Jul 25th, 2014

Please see the below code in Java"java import java.text.DecimalFormat; public class EnglishNumberToWords { private static final String[] tensNames = { "", " ten", "...

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Write a program to display all possible permutations of a given input string--if the string contains duplicate characters, you may have multiple repeated results. Here is a sample for the input cat cat,cta,act,atc,tac,tca

Jin Hyuk Cho

• Feb 3rd, 2016

A working example

Code
#include <iostream>
#include <string>
#include <set>
#include <sstream>
 
using namespace std;
 
void permute (set<char> &chars, set<string> &permuted) {
    if (chars.size() == 1) {
        stringstream charSS;
        charSS << *(chars.begin());
        permuted.insert(charSS.str());
        return;
    }
    for (set<char>::iterator it = chars.begin(); it != chars.end(); ++it) {
        // constructing remaining characters
        set<char> remainingChars(chars);
        remainingChars.erase(*it);
        // constructing empty set for results
        set<string> permutedRemainingStrings;
        permute(remainingChars, permutedRemainingStrings);
        for (set<string>::iterator rit = permutedRemainingStrings.begin();
             rit != permutedRemainingStrings.end();
             ++rit) {
            stringstream ss;
            ss << *it << *rit;
            string onePermute = ss.str();
            //cout << onePermute << endl;
            permuted.insert(onePermute);
        }
    }
}
int main () {
    
    ostream_iterator<string> output(cout, " " );
    set<char> chars = {c, a, t};
    set<string> permuted;
    permute(chars, permuted);
    copy(permuted.begin(), permuted.end(), output);
    cout << "Done!" << endl;
    
    
    return 0;
}

neha

• Aug 27th, 2015

plz see below code"cpp #include #include using namespace std; void Permutations(string str) { for(int i = 0; i < str.size(); i++) ...

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