May 06 2012 05:33 PM 3493 2 What is the difference between QTP 10. and QTP 9.0? prash036 mahesh Aug 21st, 2015 QTP 10: Keyword Driven Testing Framework Introduced. Test Re usability increased. Answer Question Select Best Answer Mar 28 2012 12:19 PM 24128 2 Write a test case for Fibonacci series? prash036 Sandhya.Kishan Profile Answers by Sandhya.Kishan Questions by Sandhya.Kishan Jun 25th, 2012 Test case for fibonacci series can be 1.When an zero is entered it should return a zero. 2.When a negative integer is entered it should not accept the value and should return an error msg. 3.When a p... Answer Question Select Best Answer Mar 28 2012 12:18 PM 4855 4 VB Script prash036 if var="a1bc23"->separate this string into two strings like, abc, 123 SatishRaja Aug 6th, 2013 Codevar="a1bc23" x=len(var) For i= 1 to x a=mid(var,i,1) If IsNumeric(a) then myNumber=myNumber+a Else myString=myString+a End If Next MsgBox myString MsgBox myNumber ratna Jun 29th, 2012 Codedim a,x a="ab1c23" for i=1 to len(a) if asc(mid(a,i,1))<>32 then if asc(mid(a,i,1))>=97 and asc(mid(a,i,1))<=122 and asc(mid(a,i,1))>=65 and asc(mid(a,i,1))<=90 then mystring=mystring&mid(a,i,1) else if asc(mid(a,i,1))>=48 and asc(mid(a,i,1))<=57 then mynumber=mynumber&mid(a,i,1) end if end if end if next msgbox (mystring) msgbox (mynumber) Answer Question Select Best Answer
May 06 2012 05:33 PM 3493 2 What is the difference between QTP 10. and QTP 9.0? prash036 mahesh Aug 21st, 2015 QTP 10: Keyword Driven Testing Framework Introduced. Test Re usability increased. Answer Question Select Best Answer
mahesh Aug 21st, 2015 QTP 10: Keyword Driven Testing Framework Introduced. Test Re usability increased.
Mar 28 2012 12:19 PM 24128 2 Write a test case for Fibonacci series? prash036 Sandhya.Kishan Profile Answers by Sandhya.Kishan Questions by Sandhya.Kishan Jun 25th, 2012 Test case for fibonacci series can be 1.When an zero is entered it should return a zero. 2.When a negative integer is entered it should not accept the value and should return an error msg. 3.When a p... Answer Question Select Best Answer
Sandhya.Kishan Profile Answers by Sandhya.Kishan Questions by Sandhya.Kishan Jun 25th, 2012 Test case for fibonacci series can be 1.When an zero is entered it should return a zero. 2.When a negative integer is entered it should not accept the value and should return an error msg. 3.When a p...
Mar 28 2012 12:18 PM 4855 4 VB Script prash036 if var="a1bc23"->separate this string into two strings like, abc, 123 SatishRaja Aug 6th, 2013 Codevar="a1bc23" x=len(var) For i= 1 to x a=mid(var,i,1) If IsNumeric(a) then myNumber=myNumber+a Else myString=myString+a End If Next MsgBox myString MsgBox myNumber ratna Jun 29th, 2012 Codedim a,x a="ab1c23" for i=1 to len(a) if asc(mid(a,i,1))<>32 then if asc(mid(a,i,1))>=97 and asc(mid(a,i,1))<=122 and asc(mid(a,i,1))>=65 and asc(mid(a,i,1))<=90 then mystring=mystring&mid(a,i,1) else if asc(mid(a,i,1))>=48 and asc(mid(a,i,1))<=57 then mynumber=mynumber&mid(a,i,1) end if end if end if next msgbox (mystring) msgbox (mynumber) Answer Question Select Best Answer
SatishRaja Aug 6th, 2013 Codevar="a1bc23" x=len(var) For i= 1 to x a=mid(var,i,1) If IsNumeric(a) then myNumber=myNumber+a Else myString=myString+a End If Next MsgBox myString MsgBox myNumber
ratna Jun 29th, 2012 Codedim a,x a="ab1c23" for i=1 to len(a) if asc(mid(a,i,1))<>32 then if asc(mid(a,i,1))>=97 and asc(mid(a,i,1))<=122 and asc(mid(a,i,1))>=65 and asc(mid(a,i,1))<=90 then mystring=mystring&mid(a,i,1) else if asc(mid(a,i,1))>=48 and asc(mid(a,i,1))<=57 then mynumber=mynumber&mid(a,i,1) end if end if end if next msgbox (mystring) msgbox (mynumber)