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else
printf("b<.7 and a>=.5");
else
printf("b>=.7");
}">output and why?main(){ float a=.5,b=.7; if(b
KishoreKNP
- Dec 2nd, 2009
Each and every float constant in C/C++ treated as double, because of this this program won't work as you expected. Add "f" like ".7f" after every float constant then it works as you expected.
Akash
- Feb 6th, 2007
The output of the above programme will be b=0.5 .7 is not stored as 0.7 ie it is stired to some value which is slightly less that 0.7 so the control will not work as expected [this is the only excception i guess for floating point nos]
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}">
could any one explan me what happens in this program. main(){ int i=10; i=(++i)/(i++); printf("i=%d",i); }
KishoreKNP
- Dec 2nd, 2009
The answer is 2, because the statementi = (++i) / (i++)will be processed from left to righti = (++10) / (10++)which meansi = 11/10++Here still ++ operator is not executedi = 1++; // 1 because it is an integer operationi = 2;if you changei = (++i) / (++i) you will see 1
