Submitted Questions

Jul 27 2006
11:28 AM

5353

1

A cow was standing on a bridge, 5feet away from the middle of the bridge. suddenly a lightning express with 90 miles/hr was coming towards the bridge from nearest end of the cow.seeeing this the cow ran towards the express and managed to escape when the train is one feet away from the bridge. if it would have ran to opposite direction(ie away from train) it would have been hit the train one ft away from the end of the bridge. Calculate the length of bridge. speed of the cow.

rajmishra4u

shiv kumar chaudhary

Aug 1st, 2006

solution as:iif we take distance of train from bridge = x+1cow speed v, and bridge length 2d then applying relative distance we got eqn. 1 = (90-v)*((d-5)/v); and in second case 0 = (90+v)*(...

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Jul 26 2006
09:22 PM

4762

0

A cow is standing 5 feet from the middle of the bridge .A train is at a distance of 2 times length of the bridge from direction in which cow is nearer to end of the bridge is coming at a speed of 90 miles/hour.If cow moves towards train it will be saved by 1 foot.If cow moves away from train it will be hit by three inches of cow(i)Find length of bridge(ii)Find cows speed

rajmishra4u

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