What is the output of the following program, When tested under JDK 5.0class ExceptionDemo{ public static void main(String[] args) { int a[] = new int[] {1,2,3,4,5}; try{ System.out.prinltln(a[6]); } catch(Exception e) { System.out.println("Catching Exception ..."); } catch(ArrayIndexOutofBoundsException ae) { System.out.println("Catching ArrayIndexOutOfBounds...

kuchipudi Prasad

• May 31st, 2012

Output is "catching exception"

sampra

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• Mar 6th, 2012

This will give error that exception caught already

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Jitendra singh

• Sep 23rd, 2015

Actually main reason that new make a class create only print my name not use object. You can create a simple program without using object this reason Java not 100% object oriented language {geshibot l...

SHWETHA g

• Aug 31st, 2015

"Static" keyword is used to a variable/method where a value of that variable has to be common to all objects created for example: bank interest rate for farmers loan common to all farmers.
where as "final" is to make a method or variable that should not be modified once after implementing.

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Manjunath_7_89

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• Mar 25th, 2016

Static methods cannot be overridden because method overriding only occurs in the context of dynamic (i.e. runtime) lookup of methods. Static methods (by their name) are looked up statically (i.e. at c...

Ramesh

• Feb 4th, 2016

If a subclass defines a class method with the same signature as a class method in the superclass, the method in the subclass hides the one in the superclass. You didn't override the method a(), because static methods are not inherited. If you had put @Override, you would have seen an error.

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sanjay637

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• May 27th, 2008

The operator == compares the content of two stringsequals method compares the references of two variablesgenerally we use == operator for comparing numbersthankssanjay bandi

jaiho123

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• May 13th, 2008

public class Test1{public static void main(String args[]){String s1="ashu";String s2="ashu";if(s1==s2)             ...

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