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difference b/w a[i] and i[a]
Is there any relation between a[i] and i[a] while using arrays..can anyone help me with this....
jintojos
- Jun 9th, 2008
Bath a[i] and i[a] are same.....the variable name 'a' contains the basic address of the array.so a[i] means base address + index 'i' and also i[a] means base address + index 'i'
paragmalshe
- May 29th, 2008
There is no difference in compilation perspectiveboth are internally converted as *(a+i) or *(i+a) which means the same thing
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1. results in a syntax error
2. outputs tim 3
3. outputs garbage
4. prints tim and terminates abruptly
">printf ("%d" ,printf {"tim") ); 1. results in a syntax error 2. outputs tim 3 3. outputs garbage 4. prints tim and terminates abruptly
alok
- Sep 11th, 2011
Syntax error
but if it is: printf("%d",printf("tim"));
then output is: tim3monuavi26
- Mar 20th, 2009
The Answer is 2. printf function returns the number of characters printed, so it returns 3 and "tim" is already printed due to the call to printf("tim"). So the output is tim 3.
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What is the output of the following program?
#define SQR(x) (x*x)
main()
{
int a,b=3;
a= SQR(b+2);
printf("%d",a);
}
">What is the output of the following program?#define SQR(x) (x*x)main(){ int a,b=3; a= SQR(b+2); printf("%d",a);}
A) 25B) 11C) ErrorD) Garbage Value
Ravi Raj Singhail
- Nov 25th, 2017
Answer is 11, Vinayaka was right all along :/
jbode
- Nov 1st, 2017
Remember that macros are just dumb text substitutions - they dont act like functions. If you specify an arithmetic expression like "b+2" as an argument to a macro, that expression wont be *evaluated*...
