vadlasrinivas

 Profile Answers by vadlasrinivas 

• May 24th, 2011

 

Yes , they point at the same reference. Check the following code
public class stringreferencetest {

/**

* @param args

*/

public static void main(String[] args) {
// TODO Auto-generated method stub

String s1 = "abc";
AnotherClassString objRef = new AnotherClassString();

if(s1==objRef.s2)
System.out.println("Pointing at same");

else


System.out.println("Not Pointing at same");
}


}

public class AnotherClassString {

String s2="";

public AnotherClassString()
{

s2 = "abc";
}

}

when you run the stringreferencetest class you will get Pointing at same as result

rajendra.panda

 Profile Answers by rajendra.panda Questions by rajendra.panda

• Jun 3rd, 2011

 

when no reference to a specified object is available in constant pool, the object is being cleared

javagek

 Profile Answers by javagek 

• Aug 30th, 2011

 

Yes your would get same reference for both the objects.
String literal pool gets cleared when your JVM exits. String literals are not getting garbage collected ever.

sampra

 Profile Answers by sampra 

• Mar 13th, 2012

 

both will point to same obj

adarsh

• Jul 30th, 2012

 

Code
public class stringreferencetest { 


 


public static void main(String[] args) { 


 


String s1 = "abc"; 


 


class AnotherClassString { 


        String s2="";


        public AnotherClassString() 


 


        {


        s2 = "abc"; 


        }


        }


 


 


 


AnotherClassString objRef = new AnotherClassString();


 


System.out.println(objRef.hashCode());


System.out.println(s1.hashCode());


 


if(s1==objRef.s2) 


System.out.println("Pointing at same");


 else


System.out.println("Not Pointing at same"); 


}


 


 


}

//Since both have different hashcode, they cant be equal (in this case referencing the same object)please explain if anyone begs to differ