word_life000

 Profile Answers by word_life000 

• Jul 7th, 2008

 

none of this

kalyan_bss

 Profile Answers by kalyan_bss 

• Jul 16th, 2008

 

none of the above

Mrinal Bhawal

 Profile Answers by Mrinal Bhawal 

• Sep 20th, 2008

 

3750 .... total number of possible cases : 2*2*2*2
favorable number : 4!/(2!*2!)
probability = 3/8

vamshiande

 Profile Answers by vamshiande 

• Dec 1st, 2008

 

answer is 625

take one family first.The probability that a child is a boy or girl is 1/2.

there fore out of  four the prob that two are boys in one family is 1/2*1/2*1/2*1/2

for 10,000 familes the prob=10,000*(1/2*1/2*1/2*1/2)=625.

ksvpavan

 Profile Answers by ksvpavan 

• Dec 4th, 2009

 

Probability should always be less than 1. So the probability is I think (3/8)¹⁰⁰⁰⁰
the no. of events for the two daughters are 6 out of total 2⁴=16 events. So the probability is 6/16=3/8 then for 10000 families the probility is (3/8)¹⁰⁰⁰⁰

geeky22

 Profile Answers by geeky22 

• Aug 21st, 2010

 

None of These

For every household there can be five possibilities :
 
1.) 1 Boy & 3 Girls
2.) 2 Boys & 2 Girls
3.) 3 Boys and 1 Girl
4.) 4 Boys and No Girl
5.) No Boy and 4 Girls

Thus the probabibility of a household having 2 daughters is : 1/5.

Thus , the final probability of every household having 2 daughters : (1/5)^1000.