In how many ways can the numbers be arranged on a dice such that 1 and 6 are onopposite faces, similarly 2 and 5 , and 3 and 4 are on opp faces

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muralikrishna

  • Oct 28th, 2006
 

Its simle. 

             There are 3 combinations, (1,2), (3,4), (5,6).

        For first three combinations i,e, for(1,2), (3,4), (5,6) the possibilities are 3!(3*2*1)=6.

       for (1,2) the possibilities are 2!(2*1)=2.

        for (3,4) the possibilities are 2!(2*1)=2.

        for (5,6) the possibilities are 2!(2*1)=2.

      There fore total=   (3!*2!*2!*2!)=48(sure).

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santosh

  • Nov 1st, 2006
 

Simple, we can hold 1 and 6 and we can make combination of 4 numbers

that is 4!=24.

we can do it in 24 ways

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nitin

  • Dec 12th, 2006
 

24....

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nitin

  • Dec 12th, 2006
 

sorry its 48 ways......... (4! ways we can arrange those 2-5 and 3-4 and twice each for 1-6)4! X 2.

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Naveen Chandra Joshi

  • Jan 2nd, 2007
 

this is only 1 way to do this.possible combination is 1. becouse dice is a simetrical think.

varadharajaperumal

  • Mar 1st, 2007
 

we can get 36...

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