There are 1/5th behind me in a race and 5/6 before me .can u tell how many participated in the race

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baskar

  • Oct 6th, 2005
 

n(1-1/5)+n(1-5/6)=n find n

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ankurmiddha

  • Oct 23rd, 2005
 

ans - 32

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devakumar

  • Oct 26th, 2005
 

(5x/6+x/5)+1=x(25x/30+6x/30)+1=x(31x/30)+1=x(31x+30)/30=xthere fore 31x+30=30xx=30

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Somnath Paramanick

  • Nov 22nd, 2005
 

Let us assume there are x number of racers excluding the person.

Therefore by the problem we have,

(1/5)x+(5/6)x=x+1

or, 31/30 x=x+1

or, x=30

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sharad vasisht

  • Nov 26th, 2005
 

Ans. 13

(x-1)/5+ 5/6(x-1)=x where x is total no.

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