Infosys Placement Paper Aug 2005 Bangalore Submitted by Sameer

1) Find the value of X,Y and Z in the following

X X X X

Y Y Y Y

Z Z Z Z

Y X X X Z

Ans:X=9 , Y=1; Z=8

2) A man starts walking at 3 pm . ha walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill , 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?

Ans: 12 km

3) A grandma has many sons; each son has as many sons as his brothers. What is her age if it's the product of the no: of her sons and grandsons plus no: of her sons?(age b/w 70 and 100).

Ans: 81 (I think)

4) An electric wire runs for 1 km b/w some no: of poles. If one pole is removed the distance b/w each pole increases by 1 2/6 (mixed fraction). How many poles were there initially?

5) There is a church tower 150 feet tall and another catholic tower at a distance of 350 feet from it which is 200 feet tall. There is one each bird sitting on top of both the towers. They fly at a constant speed and time to reach a grain in b/w the towers at the same time. At what distance from the church is the grain?

Ans: 90 (I think)

6) Days Cows

40 40
60 30
X 20
Find the no: of days ie X.

7) Puzzle on color and cards.

8) Puzzle on languages and people.

9) Find out a five digit no: which has two prime nos: and , its highest digit is 3 and lowest digit is 2 bla bla bla��..

10) Some question on truth and lie �.. I don't remember the question but I think Andrew was the ans.

Interview Candidate
Aug 10th, 2005
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Showing Answers 1 - 4 of 4 Answers

sivanarayan

Jan 13th, 2006

reply to 2nd question.
lets start with
t1 = time taken on level road. t2 = uphill. t3 = down hill;
the distance traveled uphill and down hill same so
t2*3 = 6*t3; => t2 = 2t3;---> (1)
total time = 2*t1 + t2 + t3 = 6 hours ---> (2)
2t1+3t3 = 6 -->(3)
total distance = 2*(4t1) + 3*t2+ 6*t3 ---> (4)
substitute (1) in (4)
8t1 + 12t3 => 4(2t1+3t3) then from (3)
the total distance will become 4*6
Ans: one way distance = 12km

sivanarayan

Jan 13th, 2006

4th question...
Ans : 25

Guest

Jan 13th, 2006

reply to 5th question
since speed and time are equal to reach the grain, the distance travelled is same
then from pythgorous theorm
where x is the distance of the grain from 200ft tower
150^2 + (350-x)^2 = x^2 + 200^2
(350-x)^2 - x^2 = 200^2 - 150^2
(350-x-x)(350-x+x) = (200+150)(200-150)
(350-2x)350 = 350*50
300 = 2x
x = 150ft; from 200ft tower
from church it is 200 ft
Ans = 200ft