An examiner awards the highest mark 75 and the lowest mark 25, the pass marks being 40. The moderator wants to change the highest mark to 250 and the lowest marks to 100 using the linear formula y=ax+b. the revised pass marks will be:A. 145B. 150C. 160D. 400/3

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saranya

  • Jun 11th, 2006
 

ans 145

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