hi friends ,
If the difference of two numbers is 8 and their product is 12, what is the sum of their squares?
hi friends ,
If the difference of two numbers is 8 and their product is 12, what is the sum of their squares?
Last edited by govindaraj123; 08-02-2007 at 03:59 AM. Reason: my question is placed here mistakenly. now i changed it .
There is no possible answer for this...You told their product is 12. So the possible combination is (1,12),(2,6),(3,4)
Whether the number is +ve or -ve, there is no possible for getting the difference 8.
If i am wrong then correct me...otherwise correct your question...
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suresh
The answer is 88
It is given that a -b = 8
and ab = 12
we need to calculate a^2 + b^2
We know that a^2 + b^2 = (a-b)^2 + 2ab
= 8^2 + 2 *12
= 88
To Suresh, It is not given that both a and b are integers and you are not asked to find the values of a and b.
Hope this helps you guys.
hi james,
Nice explanation. Now i am clear about the question....
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suresh
that was really tricky, so is the answer.