Is the concept of method overriding different from the concept of overloading. If so how they both differ.
Is the concept of method overriding different from the concept of overloading. If so how they both differ.
Hi nancy,there is big difference between both:
see following example
When overriding, you change the method behavior for a derived class.
e.g Clas A
{
Virtual void hi(int a)
{
}
}
Class B:A
{
public overrid void hi(int a)
{
}
}
Overloading simply involves having a method with the same name within the class.
Example for Over loading
Class A
{
class a()
{
}
class a(int a)
{
}
}
Method overriding is a feature in Object Oriented programming language. This is used to implement a method for subclass which overrides in other words replaces the implementation of the super class. Overloading the concept of providing different meaning to a object based on the context of its presence. Overloading is one type of polymorphism and this is also a feature in Object Oriented programming language.
In overriding,
The method of a sub class takes priority over its counterpart in the super-class.
where as in Overloading,
2 or more methods with same name are available (have no priority over each other) but differ in their declaration and/or definition. Either of them may be executed depending on the number and/or type of arguments passed.
Any further clarifications? Feel free to ask
Overriding is the concept of having functions of same name and signature in different classes. one in the super class can be made virtual and other can override the functionality of virtual one.
Overloading is the concept of having functions of same name, but different signature in same class. They are differentiated by the compiler by their signatures.
Using overloading and overridding, you can acheive the concept of polymorphism.
Polymorphism means "one name, multiple forms". Using one name u can do multiple of actions...
Method overloading is a compile time polymorphism and Method Overridding is a runtime polymorphism...
Compile time polymorphism means compiler knows which object assigned to which class at the compiling time....Runtime polymorphism means compiler didn't know at the compile time, it only knows at a run time...
---------------------
suresh
methjod overloading means one method can callto diffrent sub class of base class and in method overriding method in subclass takes priority over it's counterpart.
Overloading methods
1.They appear in the same class or a subclass
2.They have the same name but, have different parameter lists, and can have different return types.
An example of an overloaded method is print() in the java.io.PrintStream class
Overriding methods
It allows a subclass to re-define a method it inherits from it's superclass
overriding methods:
1. It appears in subclasses
2. They have the same name as a superclass method
3. They have the same parameter list as a superclass method
4. They have the same return type as as a superclass method
5. They have the access modifier for the overriding method may not be more restrictive than the access modifier of the superclass method
·If the superclass method is public, the overriding method must be public
·If the superclass method is protected, the overriding method may be protected or public
·If the superclass method is package, the overriding method may be packagage, protected, or public
·If the superclass methods is private, it is not inherited and overriding is not an issue
What is overloading in java ?
In Java it is possible to define two or more methods within the same class that share the same name, as long as their parameter declarations are different. When this is the case,the methods are said to be overloaded, and the process is referred to as method
overloading. Method overloading is one of the ways that Java implements polymorphism.
What is Overriding in java ?
when a method in a subclass has the same name and type signature as a method in its superclass, then the method in the subclass is said to override the method in the superclass. When an overridden method is called from within a subclass, it will always refer to the version of that method defined by the subclass.
overlaoding:functions having same name and same signature.It is a run time polymorphism.Eg: virtual function
overlaoding:function having same name but different signature.It is a compile time polymorphism.Eg: operator overloading and function overloading.
method overloading is designtime polymorphism whereas method overriding is runtime polymorphism..
In overloading the parameters should be uniqe i.e the no of parameters shud differ or if same no of parameters r there the signature shud differ
why because the compiler should know the methods in complintime only.
whereas in overriding we reimplement or change the functionality of the base class method in derived class .the no of parameters & return type shud be same ..
Let me give one example.
METHOD OVERLOADING
class human(
{
void Hand(two paremeters){
Eating}
void Hand(three parameters) {
Writing }
void Hand(Five parameters) {
Fighting }
METHOD OVERIDING
class father {
void Hand(5 parameters){
Smoking;
}
}
class child extends father{
void Hand(5 parameters){
Drinking}
Thanks
I have one confusion..
If we have a method in superclass having signature int abc(int a, int b)
and we also defined a method in the subclass having method signature int abc(int c)
then what this phenomenon will be called. This is not overriding. Is this method overloading for subclass.
any help will be appreciable..
Hi there... PPPreeti :-) ... Yes, this is called Function Overloading.
Overriding is the process of "redefining" the behavior of a parent class' method in the child class.
Overloading is the process of "creating" a new method with a lable that is already existing within the "scope" of the method.
As you may already be aware, a function or method is identified by its entire signature - not just its lable name. Lable ("abc" in your example) is only a part of the entire signature.
Therefore, when you change the signature and keep the lable name intact within a given scope, then you are overloading - regardless of whether you are doing it in a parent or child class. When you are keeping the entire signature (including the lable) intact and rewriting just the body of the function (or behavior of a method) within a child class, then you are overriding the pre-defined (or parent's) behavior of the method.
In your example, what you are doing is - "creating" a brand new signature. It so happens that one of the components that make up this signature (the lable name) is also used in a different signature (parent class' method) within the same scope.
By the way, overriding or overloading of a function occurs within the same scope of that function. If done outside the scope, it's neither overloading nor overriding. Say for example, there is a class MyClass with a function func1
class MyClass {
public:
void func1 (int a, int b)
{ for (int i =0; i++ < a; cout << b); }
};
and I define another function in a whole different class or even in a main() as
void func1 (int a, int b) { for (int i =0; i++ < a; cout << b); }
this is neither overriding (no way related to class MyClass) nor overloading (not within the scope of MyClass::func1 - so no conflict).
And a couple more things...
1. For overriding to work, the parent method must be virtual.
2. For overloading to work, the signature must change, not just the return type. Return type is not a part of the function signature. Whether the return type changes or not does not matter.
Does it confuse you further???
--Som G
Last edited by SomGollakota; 12-14-2010 at 11:09 AM.
Overriding method definitions
In a derived class, if you include a method definition that has the same name and exactly the same number and types of parameters as a method already defined in the base class, this new definition replaces the old definition of the method.
Explanation
A subclass inherits methods from a superclass. Sometimes, it is necessary for the subclass to modify the methods defined in the superclass. This is referred to as method overriding. The following example demonstrates method overriding.
Step 1
In this example we will define a base class called Circle
class Circle {
//declaring the instance variable
protected double radius;
public Circle(double radius) {
this.radius = radius;
}
// other method definitions here
public double getArea() {
return Math.PI*radius*radius;
}//this method returns the area of the circle
}// end of class circle
When the getArea method is invoked from an instance of the Circle class, the method returns the area of the circle.
Step 2
The next step is to define a subclass to override the getArea() method in the Circle class. The derived class will be the Cylinder class. The getArea() method in the Circle class computes the area of a circle, while the getArea method in the Cylinder class computes the surface area of a cylinder.
The Cylinder class is defined below.
class Cylinder extends Circle {
//declaring the instance variable
protected double length;
public Cylinder(double radius, double length) {
super(radius);
this.length = length;
}
// other method definitions here
public double getArea() { // method overriden here
return 2*super.getArea()+2*Math.PI*radius*length;
}//this method returns the cylinder surface area
}// end of class Cylinder
When the overriden method (getArea) is invoked for an object of the Cylinder class, the new definition of the method is called and not the old definition from the superclass(Circle).
Example code
This is the code to instantiate the above two classes
Circle myCircle;
myCircle = new Circle(1.20);
Cylinder myCylinder;
myCylinder = new Cylinder(1.20,2.50);
Please let me know if you need anything more
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Overriding is the Functionality by witch a programmer can change the old functionality of any function even if he does`t know that what was the old one.
But in Overloading you have to change the parameter or the return type. this is the Conceptual difference
according to overriding:
mean - overriding the previous text with new text
accessing:
if u want to access this method from the super class to sub class that must be same return type and same method name.
example
class Superclass{
void display()
{
System.out.println("this is super class display");
}
}
class Subclass extends Superclass{
void display()
{
System.out.println("this is sub class display");
}
}
class Myclass{
public static void main(String args[])
{
subclass s=new subclass();
s.display();
}
output:
this is subclass display
explanation:
the subclass method display() simply overrided the method in superclass.
problems:these steps must be follow for overriding the method
-return type must be same
-access specifier must be same
-method name is equal in both classes.
according to overloading:
one name with different arguments and the return type may be any one.
overloading the methods in the same class possible.
example:
void display();
int display(int, int);
double display(double,double);