Thread: Inherit private members of base class

Can some one here explain why private members of base class can't be inherited in derived class if derived publicly, Give some good explaination, I may know the answer, but i might be wrong, i just want to clear some doubt, asked in C++ online testing here.

private members exists only in the particular class.....so the private member cant be inherited

please.....no wrong answer...

private memebers cannot b accessed becoz of security.
it is the basic functionality of OOPs tht, the memebers of a class can b accessed by its object

private member cannot access by another class besc the life time of variable is ended in that same class .so that we cannot access the variable in outside of class but in innerclasses especially

C++ inheritance is very similar to a parent-child relationship. When a class is inherited all the functions and data member are inherited, although not all of them will be accessible by the member functions of the derived class. But there are some exceptions to it too.

Some of the exceptions to be noted in C++ inheritance are as follows.

The constructor and destructor of a base class are not inherited
the assignment operator is not inherited
the friend functions and friend classes of the base class are also not inherited.
There are some points to be remembered about C++ inheritance. The protected and public variables or members of the base class are all accessible in the derived class. But a private member variable not accessible by a derived class.

It is a well known fact that the private and protected members are not accessible outside the class. But a derived class is given access to protected members of the base class.

Private member of base class remain private to derived class even though it is publicly derived

this is d basic property of a class that its private members are not accesible outside its scope..........therefore they are not inheritted
so to inherit them we use protected instead of private
protected follows same rule + it can be inheritted to next immediate class

the private members inherited in Implicitly way to save them private but we cannt access them Directly , we can acccess them by the function

once a member of a class is declared as private, its visibility is restricted to a class.Only member functions of the same class can access those private members.

while inheriting private member in derived class,these private member become part of derived class object(note it down,but very much different from derived class own private member),but we can't direct access it thru derived class object pointer and ref and we can't write a public function in derived class to access these members(like we normally do if we have to access it thru public member).they can be accessed only by the public member function of base class in derived class object and derived class scope.

here is the sample program for this.
Just run it thru gdb and print the derived class object.
#include <iostream>
using namespace std;

class Base
{
public:
Base(int arg)ublic_data(arg),private_data(arg)
{
}
~Base(){}
void set_data(int arg)
{
private_data = arg;
}

int get_data(void)const
{
return private_data;
}

int public_data;
private:
int private_data;
};

class Derived : public Base
{
public:
Derived(int arg):Base(arg)
{
derived_data = arg;
}
~Derived()
{
}
int acces_base_private()
{
return Base::get_data();
}
private:
int derived_data;
};

int main()
{
/* object creation */
class Derived *d = new Derived(5);
/* set the data member */
d->set_data(10);
/* get the data member */
int x = d->get_data();
cout <<"x = " << x << endl;
/* direct access the public data member*/
cout <<"public data : " << d->public_data << endl;
/* direct access the private data member */
//cout <<"private_data : " << d->private_data << endl;
/* access base private thru derived public interface */
cout <<" base private: " << d->acces_base_private() << endl;

return 0;
}