Thread: array of string operation

how do we find the string length without using strlen() function?

char ch[20];
int i=0,len=0
//enter string and store it a array;

while(ch[i]!='\0')
{ len=len+1;
i++;
}
cout<<"length is" <<len;

#include<stdio.h>
#include<conio.h?
void main()
{
char ch[20];//to store string into the arry
int i=0,length=0
while(ch[i]!='\0')// while arry not equal to null. String stores at the end as null
{
length+=1;//length=length+1
i++;
}
printf("The String length is",length);
}

Originally Posted by sagar123

char ch[20];
int i=0,len=0
//enter string and store it a array;

while(ch[i]!='\0')
{ len=len+1;
i++;
}
cout<<"length is" <<len;

could you please tell , what for len is used ............ without len we can get the ans

len is used for find the length of the string

char *ch;
gets(ch);
for(int i=0;ch[i]!='\0';i++);
printf("%d",i);

To find length of an array use this

int a;

a=printf("12345");

/* a has length of string "12345" i.e 5

[QUOTE=shivaram.cunchala;12881]how do we find the string length without using strlen() function?[/QUOTby counting the number of character with spaces