Simple for loop

[jbmukund]

Hi guys,

main()
{
int i=0, j=0,z=0;
For(i=0; j,z;i++)
printf("i = %d\n",i);
}

what does this mean?????
how does the condition j,z get evaluated?

[mopodo]

Not at all.

Your snipplet does nothing.
If you set j and z to true, you have an endless loop.

here a for how it's used normally

main() {
 int i=0;

 for(i=0;i<11;i++) {
  printf("i = %d\n",i);
 }
}

[nisheedhcalicut]

Hello,

your for loop will do nothing. bcz, it will check the value of j and if it is non zero ,it will execute the printf(). Here it is zero , so wont do anything

[naveenark]

Hi guys,

main()
{
int i=0, j=0,z=0;
For(i=0; j,z;i++)
printf("i = %d\n",i);
}

what does this mean?????
how does the condition j,z get evaluated?

I have a doubt as to whether more than one condition can be tested in for loop....

[geesree]

yes!! you can test more than one condition in for loops

[mohantyrk1]

in for loop we can go for multiple condition.
your for loop , i.e. syntactically correct , but you'll not get any output, due to condition always 0 , means false . so won't execute next statement.

[ramu960]

in the for loop of the code
main(){
int i=0,j=0,z=0;
for(i=0;j,z;i++)
printf("%d",i);
}

here the variables j=0,z=0;

In the conditional part of for loop,there is a comma(,) operator which which evaluates expression from left-->right.It always considers the rightmost value.

So,the fate of loop doesn't depend on value of j.But it depends on the value of Z.
If Z has a nonzero value,then the loop will execute infinitely.
If Z has a Zero value,the loop will not be executed as conditional part is calculated as false.