Weigh the Problem

[sripri]

A goldsmith has 5 gold rings each having a different weight. Ring D weighing twice as much as ring E. Ring E is weighing four and one-half times as much as ring F. Ring F is weighing half as much as ring G. Ring G is weighing half as much as ring H. Ring H is weighing less than ring D but more than ring F.. Then which of them have the lightest weight?

[jamesravid]

F is the lightest ring among the 5 rings.


-- James

[fred]

Hi James how did you arrive at this solution. Could you post it so that it would help us?

[jamesravid]

Solution:

ring d weighing twice as much as ring e. => d= 2e and d >e

ring e is weighing four and one-half times as much as ring f. => e = (9/2) f and d > e > f

ring f is weighing half as much as ring g. => 2f = g and d > e > g > f

ring g is weighing half as much as ring h => h = 2g = 4f & d > e > h > g > f

hence f is the lightest ring.

Hope this helps
-- james.

[fred]

James the explanation was detailed and I could understand the approach well. Thanks for the brief step by step approach of the answer