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Junior Member
series...
Hello everyone...
Can you fill in the missing sets? Some addition may be in order...
12 | 14
26 | 21
59 | 28
125 | 35
??? | ??
??? | ??
1049 | 56
Try this...
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Contributing Member
Re: series...
Here is the answer....
Missing set is...
257/42 and 521/49.
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suresh
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Junior Member
Re: series...
yeah.. good job..
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Junior Member
Re: series...
12 | 14 ///12*2=24+2=26
26 | 21 //26*2=52+7= 59
59 | 28 // 59*2= 118+7=125
125 | 35 //125*2= 250+7= 257
??? | 42 // 257*2=514+7= 521
??? | 49 //521*2=1042+7= 1049
1049 | 56
and in right hand side there is diff of 7 in subequent terms am i right anchal??
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Junior Member
Re: series...
The missing sets are:
257 | 42
521 | 49
The number on the left is the sum of all the numbers above it in it's column, itself, and the number directly to it's right.The number on the right simply increases by 7 with each new set.
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Junior Member
Re: series...
still method which i adopted is also right dont u think so?
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Expert Member
Re: series...
hi arun..
For the second term alone, you added 2. for all the other terms you added 7.
so its not looking like a series.
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Expert Member
Re: series...
Hi arun Can u plz explain me why u added 2 for the second term...
Last edited by Manojks; 01-12-2007 at 02:16 AM.
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Expert Member
Re: series...
hi arun
like barbie asked, why did you added 2 first time and then 7 to all other result?
I f u can explain this , then you ans probably would be correct!
bye
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Junior Member
Re: series...
hi all
i second anchal
now i got logic thanks for feedbacking me
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Junior Member
Re: series...
ok. ,.....
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