How do you get 1000 from eight 8's

[PSharma1811]

Try this:

How will you get 1000 from eight 8's using any of these arithmetic operators

{+,-,*,/,(,)}

[sridharrganesan]

888+88+8+8+8=1000

[PSharma1811]

Good try but not correct... I said each 8 should have atleast 1 operator between them.

here is the answer:

(((8*8)+(8*8))*8)-(8+8+8) = 1000

Enjoyy

[sridharrganesan]

I said each 8 should have atleast 1 operator between them.

Hi,

This rule you are telling it now only.

Ganesan

[peeyush_jain]

Hey good question.

[prathyush]

hey man i got a good logic to remember this answer given by P sharma.
here it is,
1000=1024-24
=2^10-24
=((2^6+2^6)*2^3)-(8+8+8)
=((8*8+8*8)*8)-(8+8+8)

[kiransomavarapu]

((8*8)+(8*8)*8-(8+8+8))=1000

[jawahar manikandan]

8888-888/8=1000

[jewelia]

how do you do it is for my class and i need to find it out.
can you help me?

[abhijeetraskar]

[(8*8)+(8*8)]*8-(8+8+8)

[FANTOM]

(((8*8)+8)+((8+8)/8)+8/8)+((8*8)-(8+8))+(8+8/8))*8=1000

[sri.amit_vastava]

(8*8*8)+(8*8*8)-(8+8+8)

[amaath]

8888/8.888