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  1. #1
    Contributing Member
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    Jul 2006
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    Easy Number – Give it

    Give the positive number which is equal to its inverse plus one?


  2. #2
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    74

    Re: Easy Number – Give it

    The number is 8/5 . Is my finding right.
    I got it as follows:
    Let the number be x. Then given
    x=(1/x)+1 solving this we get x=8/5


  3. #3
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    Jun 2006
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    Re: Easy Number – Give it

    Scott,

    I think your answer is wrong.

    let me prove this...

    if x=8/5 then

    => 8/5 = 5/8 +1
    => 8/5 = 13/8
    => 8 *8/5 *13 =1
    => 64/65 =1

    which is wrong...

    I believe the x is a complex number if x^2 -x -1 =0

    -- James.


  4. #4
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    Jul 2006
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    Re: Easy Number – Give it

    James I think you have made a small mistake.
    The 8/5=5/8+1 gives
    8/5=13/8 which means
    (8/5)* (8/13) = 1 and this true because you get .98 which is equal to 1
    and not as you said 8 *8/5 *13 =1
    Also the equation for solving is x^2 -x+1 =0 and not as you mentioned x^2 -x -1 =0

    Hope my explanation is correct.


  5. #5
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    Re: Easy Number – Give it

    Scott,

    let me explain the equation part first,

    it is given that x = 1/x +1
    => x = (1+x)/x
    => x^2 = 1+x
    => x^2 -x-1 =0

    if 0.98 is equal to 1 then you answer is right


    -- James.


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