Thread: Answer This? what would be output?

hello friend pls tel the output of this pro and als describe how?


#define ROWS 3
#define COLUMNS 4
int z[ROWS][COLUMNS]={1,2,3,4,5,6,7,8,9,10,11,12}

main()
{
int a,b,c;
for(a=0;a<ROWS;++a)
{
c=999;
for(b=0;b<COLUMNS;++b)
if(z[a][b]<c)
{
c=z[a][b];
}
printf("%d",c);
}
}

Originally Posted by amar1_001

hello friend pls tel the output of this pro and als describe how?


#define ROWS 3
#define COLUMNS 4
int z[ROWS][COLUMNS]={1,2,3,4,5,6,7,8,9,10,11,12}

main()
{
int a,b,c;
for(a=0;a<ROWS;++a)
{
c=999;
for(b=0;b<COLUMNS;++b)
if(z[a][b]<c)
{
c=z[a][b];
}
printf("%d",c);
}
}

123 i s the answer

Originally Posted by amar1_001

hello friend pls tel the output of this pro and als describe how?


#define ROWS 3
#define COLUMNS 4
int z[ROWS][COLUMNS]={1,2,3,4,5,6,7,8,9,10,11,12}

main()
{
int a,b,c;
for(a=0;a<ROWS;++a)
{
c=999;
for(b=0;b<COLUMNS;++b)
if(z[a][b]<c)
{
c=z[a][b];
}
printf("%d",c);
}
}

ans:1 5 9 is the correct answer

Originally Posted by manish_tech

ans:1 5 9 is the correct answer

u r right this is the correct answer

Originally Posted by amar1_001

hello friend pls tel the output of this pro and als describe how?


#define ROWS 3
#define COLUMNS 4
int z[ROWS][COLUMNS]={1,2,3,4,5,6,7,8,9,10,11,12}

main()
{
int a,b,c;
for(a=0;a<ROWS;++a)
{
c=999;
for(b=0;b<COLUMNS;++b)
if(z[a][b]<c)
{
c=z[a][b];
}
printf("%d",c);
}
}

press f7 for compilation you know the reason for printing

hi ,
this is maddy

the o/p of given prg is 1.
description: clearly defins the value of rows =3,colomn=4
hence the matrix z has the dimension Z[3][4]
after initialization the matrix is 1 2 3 4
5 6 7 8
9 10 11 12
now in first for loop a=1,c=999,second for loop b=1
so z[1][1]=1 and after checking condition z[1][1]<999
is true then c= z[1][1]=1

i cant understand give the program

The answer is 1 since the first element of the matrix is 1.

123 is the answer

the answer is 1 , 5 , 9

nice question

The answer is 1,3,9.

Array is of z[3][4] = { 1 2 3 4
5 6 7 8
9 10 11 12
};
First Row
----------

first iteration - z[0][0] < c
1 < 999

c=1
Next Iteration - z[0][1] < 1 False so c values remains same ie c=1
1 < 1
Next iteration - z[0][2] < 1 False so c values remains same ie c=1

Next Iteration - z[0][3] < 1 False so c values remains same ie c=1

So least value element is taken from first row.

Similarly for next two rows.

hence the output would be 1,5,9.