# Line slope calculator 3x-5y=15

**Straight line given by points A[5; 0] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x-3

**Canonical form of the line equation:**3x-5y-15 = 0

**Parametric form of the line equation:**

x = 5t+5

y = 3t ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = -3

**Distance line from the origin:**d

_{0}= 2.5725

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[7.5; 1.5]

**Perpendicular Bisector equation:**5x+3y-42 = 0

**Vector OA = (5; 0) ; |OA| = 5**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 16°41'57″ = 0.2915 rad**