lemme tell u wt i askd was based on a CAT question!!
nd do u want to challenge IIMs??
lemme tell u wt i askd was based on a CAT question!!
nd do u want to challenge IIMs??
Well smart coder....
i want to clarify myself...Because "Nobody knows all the things".
That's why i need a help for other people.
Also it is very difficult to find the value for your logic...
I need a clear explantion about the 2^(4k+1).
In my next example you simply told 2^81. so you calculate the 81 like 3*3*3*3. it is single power so you can calcualte easily...if it is large then how can you find ?
If you explain this one i accept that. Waiting for your reply...
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suresh
I am not getting ur point...try to put another example!!
you want other people's view...I also agree to that..beacuse we have many intellectuals present in this forum..and I want to invite everyone to read the whole thread and then comment.
But what I asked is what I learnt at Career Launcher(a reknowned coaching for MBA) and if u ask this question to a person who is preparing for CAT will give the same answer as mine.
Thanks
Hi smartcoder,
first i want to know,
u meant 4-----3 ---- then 2 for ur problem or u r saying that is the mathematic powerof logic?
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with Thanks and Regards,
[B][I][COLOR="DarkRed"]Anushya.G[/COLOR][/I][/B]:)
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wt wt wt anushya?
I m totally confused by ur question...plz write clearly!!
ok smart coder...
Explain the following one...
This is you already posted....
2^3^4^5^.... = 2^3^(an even number) = 2^(4k +1) ...so the last digit shud be 2.
2^3^5^4.... = 2^3^(an odd number) = 2^(4k+3)... so the last digit shud be 8.
In that above you mentioned 2^3^(an even number)..
how you told that is an even number and how you write 2^(4k+1).....Also how the value 1 came that place ?
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suresh
Hi,
see, as suresh comments, i know 2^3^4 is 8^4 and accepts that nobody knows everything. We wants to know the logic that u r explaining.
In ur comment #19 u mentioned
"
i meant this
----4
--3
2
"
So, i asked, u meant and expect this logic to be followed for ur question or u r saying this is basic logic should be followed in maths.
**********
with Thanks and Regards,
[B][I][COLOR="DarkRed"]Anushya.G[/COLOR][/I][/B]:)
**********
Yes anushya ...the logic is defined already that u come top to bottom..
and suresh this is for you:
4^(any number) is an even number
so 3^4^(any number) = 3^(even number)
now 3^(even number) = 4k+1 type
like 3^2 = 9 = 4*2 + 1
and 3^4 = 81 = 4*20 + 1
ne other doubts?
please feel free to ask..
anushya this is for you..tell me the last digit for
2^1^2
hi smart coder,
Thanks for your explanation....
My question is how you defined that is (4k+1) format or (4k+3) format ?
------------------
suresh
Last edited by psuresh1982; 01-29-2007 at 03:52 AM.
if it is 3^(even) then 4K+1
or if 3^(odd) then 4K+3
hi smart coder,
Thanks for your all the information....This is the first time i hear these type of concept....I want to know the concept..that's why i ask so much of questions...now i have some idea to solve these type puzzle...still i have one more doubt...
you told me if it is 3^(even) then 4K+1.
suppose some one give the equation...2^7^6^9^4 or simply 7^6^9^4.
how can i solve this equation ? explain this also...
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suresh
Its 4.
I know only 2 concepts:
1. 2^1^2
2. the powers will be multiplied and powered to the base digit like: 2^(1*2)
I discussed with my collegues,...agree the above two.
nothing else .
Also, 2^3^4 can be calculated as 8^4 or 2^12 which results same.
2^3^4 = 2^81 will come if it is like 2^(3^4). Ofcourse brackets are important.
**********
with Thanks and Regards,
[B][I][COLOR="DarkRed"]Anushya.G[/COLOR][/I][/B]:)
**********
look there can't be answers for all such type questions...u can have answers if u think very logically
for ur question:7^6^9^4 i have a solution:
6^(any number) is of form 4k except 6^1
in ur question it is obvious dat it 6^(a large number) so it will be of type 4k
Now 7^(4k) will always end with a 1.
For u anushya:
u can c many problems when brackets are not applied but d meaning is applied like the following examples:
--4
-3
2
this is not equal to
-12
2
u cannot multiply the powers until the brackets are told explicitly..
Yeah Smart coder i agree with u...
2^3^4 is equal to 2^81....
if there is no bracket then the concept is top to bottom approach... Here first we need to find 3^4 and then 2^81
if we want to find bottom to top approach then we should use bracket its mandatory...
(2^3)^5 = 2^(3+5)
Thanks
Manoj
i knew dat atleast manoj will support me..i was waiting for u only!!!
i think my this problem wud hve cleared basic mathematics concepts of many viewers!!
dats y i put this in!!
S, i accept, until and unless the brackets are explicitly mentioned we cannot do like that. i just mentioned that i (many of us) may know these concepts only - bottom to top. i accept (2^3)^4 = 2^12 and 8^4.
We eagerly wants to know that top to bottom concepts working process for 2^3^4 (no brackets). thats it.
Fine,...let me listen ur follow ups which is fine for me.
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with Thanks and Regards,
[B][I][COLOR="DarkRed"]Anushya.G[/COLOR][/I][/B]:)
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What more you want to know anushya??
what more working process??
the process is simple
just TOP to BOTTOM!!!
dats it!!
feel free to ask more!!