An array of 100 elements consists of only 0's and 1's. One should count the number of 1's or 0's with a very few lines of C program. One method is to sum all the elements to get the number of 1's. But there should be a built-in command to get the answer in a single line of program, I suppose. Please notify me if anyone knows the answer.

Question asked by visitor Vanitha

in C you can do it in one line

for(i = 0; i < ARR_SIZ ; i++) (num[i] == 1) ? ones++: zeros++;

a sample program could be...
------------------

#include <stdio.h>
#define ARR_SIZ 100

int main()
{

int num[ARR_SIZ],
i,
ones,
zeros;

ones = 0;
zeros = 0;

/* array fill */
for (i = 0; i < ARR_SIZ; i++)
num[i] = (i % 2) == 0 ? 1: 0;

/* array processing */
for(i = 0; i < ARR_SIZ ; i++)
(num[i] == 1) ? ones++: zeros++;

printf("\nones: %d\tzeros: %d\n",
ones,
zeros);

return 0;

}
------------

hth