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Thread: Weigh the Problem

  1. #1
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    Jul 2006
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    Question Weigh the Problem

    A goldsmith has 5 gold rings each having a different weight. Ring D weighing twice as much as ring E. Ring E is weighing four and one-half times as much as ring F. Ring F is weighing half as much as ring G. Ring G is weighing half as much as ring H. Ring H is weighing less than ring D but more than ring F.. Then which of them have the lightest weight?


  2. #2
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    Jun 2006
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    Re: Weigh the Problem

    F is the lightest ring among the 5 rings.


    -- James


  3. #3
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    May 2006
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    Re: Weigh the Problem

    Hi James how did you arrive at this solution. Could you post it so that it would help us?


  4. #4
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    Re: Weigh the Problem

    Solution:

    ring d weighing twice as much as ring e. => d= 2e and d >e

    ring e is weighing four and one-half times as much as ring f. => e = (9/2) f and d > e > f

    ring f is weighing half as much as ring g. => 2f = g and d > e > g > f

    ring g is weighing half as much as ring h => h = 2g = 4f & d > e > h > g > f

    hence f is the lightest ring.

    Hope this helps
    -- james.


  5. #5
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    May 2006
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    71

    Re: Weigh the Problem

    James the explanation was detailed and I could understand the approach well. Thanks for the brief step by step approach of the answer


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