Print elements in array

the expected output of the following C program is to print the elements in the array. But when actually run, it doesn't do so.

#include
#define
TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))

int array[] = {23,34,12,17,204,99,16};

int main()
{
int d;

for(d=-1;d <= (TOTAL_ELEMENTS-2);d++)
printf("%dn",array[d+1]);

return 0;
}

Find out what's going wrong.

u can also take the below example for java

(Toggle Plain Text)
System.out.println ( "All the values in the array are: " );
for ( T x: array1 )
System.out.println ( x );System.out.println ( "All the values <strong class="highlight">in</strong> the <strong class="highlight">array</strong> are: " );
for ( T x: array1 )
System.out.println ( x );
Change T to whatever the type of the array is. Or, if you aren't up to the latest version of Java:

(Toggle Plain Text)
System.out.println ( "All the values in the array are: " );
for ( int i = 0; i < array1.length; i++ )
System.out.println ( array1[i] );System.out.println ( "All the values <strong class="highlight">in</strong> the <strong class="highlight">array</strong> are: " );
for ( int i = 0; i < array1.length; i++ )
System.out.println ( array1[i] );

I think because u have used array name before declaration may be tat's why it's not working.......
coz compiler needs to have information about the array declaration..

Make this small change in the code.

for(d=-1;d <= (int)(TOTAL_ELEMENTS-2) ;d++)

Since Sizeof() returns unsigned int , thus it might be the problem while comparing a int with an unsigned int...

Hi,

Thats a right answer..