File input/output in Pl/Sql

While creating a text file using utl_file it is showing error message ora-29280: invalid directory path

I have set the path in init.ora in server as
utl_file_dir = 'd:\orahome\bin'

This is procedure code
create or replace procedure test_filehandling as
filehandle utl_file.file_type;
writemessage varchar2(200);
begin
filehandle := utl_file.fopen('\\10.15.1.197\d\orahome\bin','test.txt','w');
writemessage := 'this is created for testing purpose \n' || ' \n this is the second line';
utl_file.putf(filehandle,writemessage);
writemessage := ' line by line code using putline';
utl_file.put_line(filehandle,writemessage);
utl_file.fflush(filehandle);
utl_file.fclose(filehandle);
end;
/
could anyone suggest me what is wrong with the code?

To check Directory name,directory path use this query
select directory_name , directory_path from all_directories
To create Directory name use this query
CREATE OR REPLACE DIRECTORY TEST_UTIL AS 'C:\TEMP'
use directory name in place of \\10.15.1.197\d\orahome\bin
ex: filehandle := utl_file.fopen('test_util','test.txt','w'); Then ur procedure will work

Thank you for you suggestion. Now I am getting error
ORA-29283: invalid file operation
ORA-06512: at "SYS.UTL_FILE", line 449
ORA-29283: invalid file operation
ORA-06512: at "PAYLIVE.TEST_FILEHANDLING", line 9

and 9th line in my code is
FILEHANDLE := UTL_FILE.FOPEN('TEST_UTIL','TEST.TXT','W');

Could you suggest what might be the problem?

The problem was solved. In server C Drive is not in shared mode.

Can't we give directly existing folder path like this
\\10.15.1.197\D\MYFOLDER
without creating a directory as
CREATE OR REPLACE DIRECTORY TEST_UTIL AS 'C:\TEMP'

I tried but once again it is showing message ORA-29280: invalid directory path.

What is the reason?

oracle refers to the virtual directory created not to system directory.