If X gives Y seven apples, then Y will then have five times as many as X would have, however, if Y give X seven apples, then both X and Y will have the same number of apples. How many apples do X currently have?
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If X gives Y seven apples, then Y will then have five times as many as X would have, however, if Y give X seven apples, then both X and Y will have the same number of apples. How many apples do X currently have?
x=14
y = 28
:)
Let no of apples with x as n1
Let no of apples with y as n2
Then according to first condition
n2+7 = 5* (n1-7)-----------------------(1)
From the second condition we have
n2-7=n1+7-----------------------------(2)
Thus solving (1) and (2) we have
[b]n1=14 n2=28[/b]
Five girls took part in a race. Alison finished before Bunty but behind Clare. Debby finished before Emma but behind Bunty. What was the finishing order?
Finishing Order Is
[B]1.Clare
2.Alison
3.Bunty
4.Debby
5.Emma[/B]
Call No. of apple of Y is n1
Call No. of apple of X is n2
We have :
n1 + 5 = 5*(n2 - 5) => n1 = 5*n2 - 30 (1)
on the other hand :
n1 - 7 = n2 + 7 => n1 = n2 + 14 (2)
From (1) and (2), we have
n1 = 25
n2 = 11
I'm sure this is the correct answer.
14 & 28 is not the correct answer.