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A goldsmith has 5 gold rings each having a different weight. Ring D weighing twice as much as ring E. Ring E is weighing four and one-half times as much as ring F. Ring F is weighing half as much as ring G. Ring G is weighing half as much as ring H. Ring H is weighing less than ring D but more than ring F.. Then which of them have the lightest weight?
F is the lightest ring among the 5 rings.
-- James
Hi James how did you arrive at this solution. Could you post it so that it would help us?
Solution:
ring d weighing twice as much as ring e. => d= 2e and d >e
ring e is weighing four and one-half times as much as ring f. => e = (9/2) f and d > e > f
ring f is weighing half as much as ring g. => 2f = g and d > e > g > f
ring g is weighing half as much as ring h => h = 2g = 4f & [b]d > e > h > g > f[/b]
hence f is the lightest ring.
Hope this helps :)
-- james.
James the explanation was detailed and I could understand the approach well. Thanks for the brief step by step approach of the answer