array of string operation

how do we find the string length without using strlen() function?

There are many ways of doing it. Just running through the characters of the string inside a for/while loop will do the trick.

Cheers!
Kalayama

char ch[20];
int i=0,len=0
//enter string and store it a array;

while(ch[i]!='\0')
{ len=len+1;
i++;
}
cout<<"length is" <<len;

#include<stdio.h>
#include<conio.h?
void main()
{
char ch[20];//to store string into the arry
int i=0,length=0
while(ch[i]!='\0')// while arry not equal to null. String stores at the end as null
{
length+=1;//length=length+1
i++;
}
printf("The String length is",length);
}

[QUOTE=sagar123;16602]char ch[20];
int i=0,len=0
//enter string and store it a array;

while(ch[i]!='\0')
{ len=len+1;
i++;
}
cout<<"length is" <<len;[/QUOTE]

could you please tell , what for len is used ............ without len we can get the ans

len is used for find the length of the string

char *ch;
gets(ch);
for(int i=0;ch[i]!='\0';i++);
printf("%d",i);

To find length of an array use this

int a;

a=printf("12345");

/* a has length of string "12345" i.e 5

[QUOTE=shivaram.cunchala;12881]how do we find the string length without using strlen() function?[/QUOTby counting the number of character with spaces