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There are five persons A,B,C,D,E whose birthdays occur at the consecutive days. Birthday of A is some days or day before C & birthday of B is exactly the same days or day after E. D is two days older than E. If birth day of C is on Wednesday then find out the birthdays of other.
It is given that D is two days older than E
[U]D[/U] _ [U]E[/U]
It is also given than difference between A&C brithdays is same as difference between birthdays of E and B.
Hence the only possible order is [U]D[/U] [U]A[/U] [U]E[/U] [U]C[/U] [U]B[/U]
So C born on Wednesday then other's birthdays would be
D - Sunday
A - Monday
E - Tuesday
B - Thursday
I think the right answer is
D-Monday
A-Tuesday
C-Wednesday
E-Thursday
B-Friday
My solution to this, gave me a result as that of jamesravid's.
so,
I Strongly agree with jamesravid.
Monday---A
Tuesday--D
Wednesday-- C
Thursday-- E
Friday----B
I am right?
sorry rpguppa ...you are wrong as d difference between bdays of A and C is not equal to diff b/w bdays of E and B.
jamesravid has already posted d correct solution.
[QUOTE=kumar_sarma2000;12221]There are five persons A,B,C,D,E whose birthdays occur at the consecutive days. Birthday of A is some days or day before C & birthday of B is exactly the same days or day after E. D is two days older than E. If birth day of C is on Wednesday then find out the birthdays of other.[/QUOTE]
a 's bday b4 c--------1st condn
b 's after e-----------2nd cond
d's 2 day older to e
c's on wed , d's on tue ,e's on thu ,b 's on fri,a's on mon